| Doubles | |
|---|---|
| 2019 Open Sud de France | |
| Champions |
Ivan Dodig
Édouard Roger-Vasselin |
| Runners-up |
Benjamin Bonzi
Antoine Hoang |
| Score | 6–4, 6–3 |
| Draw | 16 |
| Seeds | 4 |
Ken and Neal Skupski were the defending champions, [1] but lost in the quarterfinals to Benjamin Bonzi and Antoine Hoang.
Ivan Dodig and Édouard Roger-Vasselin won the title, defeating Bonzi and Hoang in the final, 6–4, 6–3.
Seeds
-
Ivan Dodig /
Édouard Roger-Vasselin (champions)
-
Austin Krajicek /
Artem Sitak (first round) -
Ken Skupski /
Neal Skupski (quarterfinals) -
Radu Albot /
Marcel Granollers (quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 |
I Dodig
É Roger-Vasselin
| 6 | 7 | ||||||||||||||||||||||||
D Kudla 
A Mies
| 1 | 5 | 1 |
I Dodig
É Roger-Vasselin
| 66 | 6 | [10] | ||||||||||||||||||||
M Matkowski 
P Oswald
| 2 | 6 | [10] |
M Matkowski
P Oswald
| 78 | 1 | [7] | ||||||||||||||||||||
| PR |
S Darcis
D Goffin
| 6 | 1 | [2] | 1 |
I Dodig
É Roger-Vasselin
| 6 | 77 | |||||||||||||||||||
| 4 |
R Albot
M Granollers
| 6 | 77 |
L Paes
B Paire
| 3 | 63 | |||||||||||||||||||||
|
U Humbert
N Mahut
| 4 | 63 | 4 |
R Albot
M Granollers
| 1 | 4 | |||||||||||||||||||||
|
L Paes
B Paire
| 6 | 6 |
L Paes
B Paire
| 6 | 6 | ||||||||||||||||||||||
|
J Eysseric
G Simon
| 4 | 2 | 1 |
I Dodig
É Roger-Vasselin
| 6 | 6 | |||||||||||||||||||||
| WC |
C Lestienne
L Pouille
| 4 | 3 | WC |
B Bonzi
A Hoang
| 4 | 3 | ||||||||||||||||||||
| WC |
B Bonzi
A Hoang
| 6 | 6 | WC |
B Bonzi
A Hoang
| 6 | 7 | ||||||||||||||||||||
R Lindstedt
T Pütz
| 3 | 4 | 3 |
K Skupski
N Skupski
| 2 | 5 | |||||||||||||||||||||
| 3 |
K Skupski
N Skupski
| 6 | 6 | WC |
B Bonzi
A Hoang
| 6 | 6 | ||||||||||||||||||||
H Nys 
D Shapovalov
| 6 | 65 | [10] |
L Bambridge
J O'Mara
| 4 | 4 | |||||||||||||||||||||
|
J Chardy
F Martin
| 4 | 77 | [7] |
H Nys
D Shapovalov
| 6 | 5 | [8] | ||||||||||||||||||||
|
L Bambridge
J O'Mara
| 6 | 6 |
L Bambridge
J O'Mara
| 3 | 7 | [10] | |||||||||||||||||||||
| 2 |
A Krajicek
A Sitak
| 4 | 2 | ||||||||||||||||||||||||
References
- ^ "British brothers Ken and Neal Skupski win first ATP World Tour title together". BBC. 12 February 2018. Retrieved 2 February 2019.
External links
| Doubles | |
|---|---|
| 2019 Open Sud de France | |
| Champions |
Ivan Dodig
Édouard Roger-Vasselin |
| Runners-up |
Benjamin Bonzi
Antoine Hoang |
| Score | 6–4, 6–3 |
| Draw | 16 |
| Seeds | 4 |
Ken and Neal Skupski were the defending champions, [1] but lost in the quarterfinals to Benjamin Bonzi and Antoine Hoang.
Ivan Dodig and Édouard Roger-Vasselin won the title, defeating Bonzi and Hoang in the final, 6–4, 6–3.
Seeds
-
Ivan Dodig /
Édouard Roger-Vasselin (champions)
-
Austin Krajicek /
Artem Sitak (first round)
-
Ken Skupski /
Neal Skupski (quarterfinals)
-
Radu Albot /
Marcel Granollers (quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 |
I Dodig
É Roger-Vasselin
| 6 | 7 | ||||||||||||||||||||||||
|
D Kudla
A Mies
| 1 | 5 | 1 |
I Dodig
É Roger-Vasselin
| 66 | 6 | [10] | ||||||||||||||||||||
|
M Matkowski
P Oswald
| 2 | 6 | [10] |
M Matkowski
P Oswald
| 78 | 1 | [7] | ||||||||||||||||||||
| PR |
S Darcis
D Goffin
| 6 | 1 | [2] | 1 |
I Dodig
É Roger-Vasselin
| 6 | 77 | |||||||||||||||||||
| 4 |
R Albot
M Granollers
| 6 | 77 |
L Paes
B Paire
| 3 | 63 | |||||||||||||||||||||
|
U Humbert
N Mahut
| 4 | 63 | 4 |
R Albot
M Granollers
| 1 | 4 | |||||||||||||||||||||
|
L Paes
B Paire
| 6 | 6 |
L Paes
B Paire
| 6 | 6 | ||||||||||||||||||||||
|
J Eysseric
G Simon
| 4 | 2 | 1 |
I Dodig
É Roger-Vasselin
| 6 | 6 | |||||||||||||||||||||
| WC |
C Lestienne
L Pouille
| 4 | 3 | WC |
B Bonzi
A Hoang
| 4 | 3 | ||||||||||||||||||||
| WC |
B Bonzi
A Hoang
| 6 | 6 | WC |
B Bonzi
A Hoang
| 6 | 7 | ||||||||||||||||||||
|
R Lindstedt
T Pütz
| 3 | 4 | 3 |
K Skupski
N Skupski
| 2 | 5 | |||||||||||||||||||||
| 3 |
K Skupski
N Skupski
| 6 | 6 | WC |
B Bonzi
A Hoang
| 6 | 6 | ||||||||||||||||||||
|
H Nys
D Shapovalov
| 6 | 65 | [10] |
L Bambridge
J O'Mara
| 4 | 4 | |||||||||||||||||||||
|
J Chardy
F Martin
| 4 | 77 | [7] |
H Nys
D Shapovalov
| 6 | 5 | [8] | ||||||||||||||||||||
|
L Bambridge
J O'Mara
| 6 | 6 |
L Bambridge
J O'Mara
| 3 | 7 | [10] | |||||||||||||||||||||
| 2 |
A Krajicek
A Sitak
| 4 | 2 | ||||||||||||||||||||||||
References
- ^ "British brothers Ken and Neal Skupski win first ATP World Tour title together". BBC. 12 February 2018. Retrieved 2 February 2019.