This is a Wikipedia
user talk page. This is not an encyclopedia article or the talk page for an encyclopedia article. If you find this page on any site other than Wikipedia, you are viewing a mirror site. Be aware that the page may be outdated and that the user whom this page is about may have no personal affiliation with any site other than Wikipedia. The original talk page is located at https://en.wikipedia.org/wiki/User_talk:Justin545. |
Welcome!
Hello, Justin545, and welcome to Wikipedia! Thank you for your contributions. I hope you like the place and decide to stay. Here are some pages that you might find helpful:
I hope you enjoy editing here and being a
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ReluctantPhilosopher (
talk)
17:13, 16 February 2008 (UTC)
{{helpme}}
What type of questions can I ask when I use {{
helpme}}? I have some questions about quantum mechanics to discuss but I am not sure if it is suitable to use {{
helpme}}...
Justin545 ( talk) 23:54, 22 February 2008 (UTC)
{{helpme}}
should only be used for questions such as using wikipedia. For content questions like physics you should go to
Wikipedia:Reference desk. Hope this helps, if you have any questions feel free to ask me on my talkpage.--
Sunny910910 (
talk|
Contributions|
Guest)
23:57, 22 February 2008 (UTC)I just wanted to mention that I finally posted a reply in the quantum computing thread. It might not show up in your watchlist because the thread is now in the archives at Wikipedia:Reference_desk/Archives/Science/2008_February_23. -- BenRG ( talk) 16:25, 27 February 2008 (UTC)
Having seen you post several times in the mathematics section recently, I decided to take a look at your user page and was surprised to learn that you believe 0.99999.... doesn't equal 1. Considering that your a skeptic, I'm not terribly surprised by that, and it is good to question things, even generally excepted ideas. So to justify why 0.999...=1 one needs to thoroughly understand the ... notation's definition. The ellipsis notation (...) is used to indicate that a pattern in the digits of a decimal notation is repeated without end (infinite). so 0.9999... mean that the pattern of 9's in decimal places of successively decreasing value is repeated without end. Given the definition of ... it is easy to show either through limits or a converging summation, that 0.999...=1. There are also ways of showing it without using "higher" mathematics but those ways aren't always so convincing, it is certainly not the most intuitive result in mathematics. (One thing I must point out about the ... notation is that when it is used on a finite decimal that does not contain two or more repetitions of a pattern, it indicates that the decimal is infinite in length and does not imply that there is or is not a pattern) A math-wiki ( talk) 23:29, 20 March 2008 (UTC)
(1) |
is so small compaired to infinity so we can ignore the difference between 1/ and without changing the results for "some" cases. But we can not "always" ignore the difference between 1/ and for "all" cases, since the difference between 1/ and is significant for some cases. For example, we should NOT ignore the difference between 1/ and for the case , substitute the limit directly by 1/ and will yield two different results for the case, which means the difference between 1/ and is significant for the case. For another example, is NOT "always" equivalent to since substitute the limit directly by and will not always yield the same results for all of kind of 's and 's. is "said" to be equivalent to only when substitute the limit directly by and will yield the same results for some 's and 's. When is "said" to be equivalent to , it means the difference between and is trivial and therefore can be ignored for the case. |
And for a simply proof that 0.999...=1,
, I assume you agree that this is a true mathematical statement, then
If 0.333... is interpreted as base 10 would imply, then it's equivalent to
A math-wiki ( talk) 23:47, 24 March 2008 (UTC)
!= | This user believes that 0.99999... does NOT equal 1. |
, if and only if, so if we have , then is defined on but if we consider that is defined for that includes p=0!! The limit to exists at p=0 because f is defined for all x in an interval (a,b), except at p=0 which is admissible under the definition of the Limit of a function. So the limit exists, despite f not being well-defined for x=0. This limit is evaluated as follows, , direct substitution yields 0/0, so instead we define another function which is equal to f(x) on (a,b) except at x=0, and is continuous on [a,b], g(x)=1, since then the limit may be evaluated by direct substitution since g is defined at x=0, the reason this works conceptually, is since g is continuous, then we know that it will answer the question what is f approaching as x approaches 0 (in both directions). And using graphical reasoning, the graph of f is a line with m=0, that that passes through (1,1)
It should also be noted that the proof of 0.999...=1 has no variables, and all of the quantities involved are non-zero, so it is perfectly ok, even under fully formal conditions to cancel with any conditions, since there are no variables to worry about. So the proof above in without error in that regard.
I was surprised that you believed due to the fact that your posts had shown considerable confidence with at least Calculus level mathematics, so I presumed that you would have justified why 0.999...=1 for yourself already. You're absolutely right that you should approach science and especially mathematics in the mind set of a skeptic. I too questioned that result when it was first presented to me, but after completing a proof like one I provided with fractions, I was convinced of the validity of that claim. I was even more skeptical of the chain rule when it was first presented to me, but I eventually studied the proof in my text with sufficient thoroughness to assure myself of it's validity. I decided to start this post since from what I knew of your mindset, I suspected that you would be able to remain rational thorough the discussion, and you have much to my delite and appreciation. A math-wiki ( talk) 10:11, 25 March 2008 (UTC)
References
Add or remove whitespace as you wish. siℓℓy rabbit ( talk) 13:38, 5 February 2009 (UTC)
![]() |
The Working Wikipedian's Barnstar |
Thanks for the nice numbering of equations in BKL singularity. This helped a lot. Lantonov ( talk) 15:19, 18 February 2009 (UTC) |
Template:AngleBracket has been nominated for deletion. You are invited to comment on the discussion at
the template's entry on the Templates for discussion page. Thank you.
Plastikspork
―Œ(talk)
17:43, 6 November 2009 (UTC)
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22:43, 9 January 2011 (UTC)
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Hello member of Category:Wikipedians who use IRC! You are invited to join an ongoing discussion on Wikipedia talk:IRC/wikipedia-en-help aimed at defining a policy for prerequisites to being a helper in the "#wikipedia-en-help connect" channel in a section titled "New helper policy".
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Dialectric (
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14:43, 1 May 2015 (UTC)
"Could" is not an adjective, it's a Past form. "Can", and "cant", have no adjective. However, "can" = "is able to", and "can't" = "is unable to", while "is unable" - has an adjective: "unable", so you can say: "it is an error of table unable to be displayed".
Just losing weight overall could help, by eating fewer total calories. Of course, you need to get enough protein (I think 55 g per day is the general recommendation, but can go lower if your doctor requires it), but no excess. Beans, fish (not fried !), and nuts (not salted !) are a good choice for protein sources. Vegetables provide lots of nutrients but few calories, so they are a good choice. Keep the carbs low, such as grains, potatoes, and sugar. Also avoid artificial sweeteners. Surprisingly, eating fats don't seem to make you gain fat, but limit saturated fats and avoid artificial trans fats entirely.
You left open the possibility or anaerobic exercise. If so, any exercise can help, even just walking a bit each day. StuRat ( talk) 14:21, 9 July 2015 (UTC)
From your method of editing and the subject material that interests you I suspect you may be a sock of User Sagittarian Milky Way. See the discussion here. My apology for the delay in notification. μηδείς ( talk) 21:16, 21 September 2015 (UTC)
![]() | This help request has been answered. If you need more help, you can , contact the responding user(s) directly on their user talk page, or consider visiting the Teahouse. |
I have made a long edit on WP:sandbox before (look here). I would like to know if such kind of edit is inappropriate. And did I violate any guidelines of editing sandbox?
Justin545 ( talk) 01:59, 26 September 2015 (UTC)
A tag has been placed on User:Justin545/Blog comments requesting that it be speedily deleted from Wikipedia. This has been done under section U5 of the criteria for speedy deletion, because the page appears to consist of writings, information, discussions, and/or activities not closely related to Wikipedia's goals. Please note that Wikipedia is not a free Web hosting service. Under the criteria for speedy deletion, such pages may be deleted at any time.
If you think this page should not be deleted for this reason, you may contest the nomination by visiting the page and clicking the button labelled "Contest this speedy deletion". This will give you the opportunity to explain why you believe the page should not be deleted. However, be aware that once a page is tagged for speedy deletion, it may be removed without delay. Please do not remove the speedy deletion tag from the page yourself, but do not hesitate to add information in line with Wikipedia's policies and guidelines. If the page is deleted, and you wish to retrieve the deleted material for future reference or improvement, then please contact the deleting administrator, or if you have already done so, you can place a request here. Mys_721tx ( talk) 09:20, 3 November 2015 (UTC)
Hi,
You appear to be eligible to vote in the current
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Hello, Justin545. Voting in the 2017 Arbitration Committee elections is now open until 23.59 on Sunday, 10 December. All users who registered an account before Saturday, 28 October 2017, made at least 150 mainspace edits before Wednesday, 1 November 2017 and are not currently blocked are eligible to vote. Users with alternate accounts may only vote once.
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(Courtesy ping of
Jonesey95, who is often helpful in fixing lint errors.) Justin545: You recently edited
Template:Numbered block, and now there are several
pages with Multiline table in list lint errors. I started in User space and fixed two pages,
User:Justin545 and
User:Mim.cis/sandbox/Derivation of Landmark LDDMM Conditions, before I discovered that changing {{NumBlk||...}}
to {{NumBlk|:|...}}
made the lint error go away, and only then did I discover that you had edited
Template:Numbered block. So I am pausing now to inform you of this. Please see if you can fix
Template:Numbered block to avoid the Multiline table in list lint error. —
Anomalocaris (
talk)
05:44, 2 May 2024 (UTC)
NumBlk
if I understand correctly. Probably I need to revert it and try to figure out the cause ...
Justin545 (
talk)
06:54, 2 May 2024 (UTC)This is a Wikipedia
user talk page. This is not an encyclopedia article or the talk page for an encyclopedia article. If you find this page on any site other than Wikipedia, you are viewing a mirror site. Be aware that the page may be outdated and that the user whom this page is about may have no personal affiliation with any site other than Wikipedia. The original talk page is located at https://en.wikipedia.org/wiki/User_talk:Justin545. |
Welcome!
Hello, Justin545, and welcome to Wikipedia! Thank you for your contributions. I hope you like the place and decide to stay. Here are some pages that you might find helpful:
I hope you enjoy editing here and being a
Wikipedian! Please
sign your messages on
discussion pages using four
tildes (~~~~); this will automatically insert your username and the date. If you need help, check out
Wikipedia:Questions, ask me on my talk page, or ask your question and then place {{
helpme}}
before the question on your talk page. Again, welcome! Have fun editing Wikipedia !!
ReluctantPhilosopher (
talk)
17:13, 16 February 2008 (UTC)
{{helpme}}
What type of questions can I ask when I use {{
helpme}}? I have some questions about quantum mechanics to discuss but I am not sure if it is suitable to use {{
helpme}}...
Justin545 ( talk) 23:54, 22 February 2008 (UTC)
{{helpme}}
should only be used for questions such as using wikipedia. For content questions like physics you should go to
Wikipedia:Reference desk. Hope this helps, if you have any questions feel free to ask me on my talkpage.--
Sunny910910 (
talk|
Contributions|
Guest)
23:57, 22 February 2008 (UTC)I just wanted to mention that I finally posted a reply in the quantum computing thread. It might not show up in your watchlist because the thread is now in the archives at Wikipedia:Reference_desk/Archives/Science/2008_February_23. -- BenRG ( talk) 16:25, 27 February 2008 (UTC)
Having seen you post several times in the mathematics section recently, I decided to take a look at your user page and was surprised to learn that you believe 0.99999.... doesn't equal 1. Considering that your a skeptic, I'm not terribly surprised by that, and it is good to question things, even generally excepted ideas. So to justify why 0.999...=1 one needs to thoroughly understand the ... notation's definition. The ellipsis notation (...) is used to indicate that a pattern in the digits of a decimal notation is repeated without end (infinite). so 0.9999... mean that the pattern of 9's in decimal places of successively decreasing value is repeated without end. Given the definition of ... it is easy to show either through limits or a converging summation, that 0.999...=1. There are also ways of showing it without using "higher" mathematics but those ways aren't always so convincing, it is certainly not the most intuitive result in mathematics. (One thing I must point out about the ... notation is that when it is used on a finite decimal that does not contain two or more repetitions of a pattern, it indicates that the decimal is infinite in length and does not imply that there is or is not a pattern) A math-wiki ( talk) 23:29, 20 March 2008 (UTC)
(1) |
is so small compaired to infinity so we can ignore the difference between 1/ and without changing the results for "some" cases. But we can not "always" ignore the difference between 1/ and for "all" cases, since the difference between 1/ and is significant for some cases. For example, we should NOT ignore the difference between 1/ and for the case , substitute the limit directly by 1/ and will yield two different results for the case, which means the difference between 1/ and is significant for the case. For another example, is NOT "always" equivalent to since substitute the limit directly by and will not always yield the same results for all of kind of 's and 's. is "said" to be equivalent to only when substitute the limit directly by and will yield the same results for some 's and 's. When is "said" to be equivalent to , it means the difference between and is trivial and therefore can be ignored for the case. |
And for a simply proof that 0.999...=1,
, I assume you agree that this is a true mathematical statement, then
If 0.333... is interpreted as base 10 would imply, then it's equivalent to
A math-wiki ( talk) 23:47, 24 March 2008 (UTC)
!= | This user believes that 0.99999... does NOT equal 1. |
, if and only if, so if we have , then is defined on but if we consider that is defined for that includes p=0!! The limit to exists at p=0 because f is defined for all x in an interval (a,b), except at p=0 which is admissible under the definition of the Limit of a function. So the limit exists, despite f not being well-defined for x=0. This limit is evaluated as follows, , direct substitution yields 0/0, so instead we define another function which is equal to f(x) on (a,b) except at x=0, and is continuous on [a,b], g(x)=1, since then the limit may be evaluated by direct substitution since g is defined at x=0, the reason this works conceptually, is since g is continuous, then we know that it will answer the question what is f approaching as x approaches 0 (in both directions). And using graphical reasoning, the graph of f is a line with m=0, that that passes through (1,1)
It should also be noted that the proof of 0.999...=1 has no variables, and all of the quantities involved are non-zero, so it is perfectly ok, even under fully formal conditions to cancel with any conditions, since there are no variables to worry about. So the proof above in without error in that regard.
I was surprised that you believed due to the fact that your posts had shown considerable confidence with at least Calculus level mathematics, so I presumed that you would have justified why 0.999...=1 for yourself already. You're absolutely right that you should approach science and especially mathematics in the mind set of a skeptic. I too questioned that result when it was first presented to me, but after completing a proof like one I provided with fractions, I was convinced of the validity of that claim. I was even more skeptical of the chain rule when it was first presented to me, but I eventually studied the proof in my text with sufficient thoroughness to assure myself of it's validity. I decided to start this post since from what I knew of your mindset, I suspected that you would be able to remain rational thorough the discussion, and you have much to my delite and appreciation. A math-wiki ( talk) 10:11, 25 March 2008 (UTC)
References
Add or remove whitespace as you wish. siℓℓy rabbit ( talk) 13:38, 5 February 2009 (UTC)
![]() |
The Working Wikipedian's Barnstar |
Thanks for the nice numbering of equations in BKL singularity. This helped a lot. Lantonov ( talk) 15:19, 18 February 2009 (UTC) |
Template:AngleBracket has been nominated for deletion. You are invited to comment on the discussion at
the template's entry on the Templates for discussion page. Thank you.
Plastikspork
―Œ(talk)
17:43, 6 November 2009 (UTC)
If this is the first article that you have created, you may want to read the guide to writing your first article.
You may want to consider using the Article Wizard to help you create articles.
Thank you for experimenting with Wikipedia. Your test worked, and the page that you created has been or soon will be deleted. Please use the sandbox for any other tests you want to do. Take a look at the welcome page if you would like to learn more about contributing to our encyclopedia.
If you think that this notice was placed here in error, you may contest the deletion by adding {{hang on}}
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the page that has been nominated for deletion (just below the existing speedy deletion, or "db", tag; if no such tag exists, then the page is no longer a speedy delete candidate and adding a hang-on tag is unnecessary), coupled with adding a note on
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userfy the page or email a copy to you.
Mhiji
22:43, 9 January 2011 (UTC)
The article MicroXwin has been proposed for deletion because of the following concern:
While all constructive contributions to Wikipedia are appreciated, content or articles may be deleted for any of several reasons.
You may prevent the proposed deletion by removing the {{proposed deletion/dated}}
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Please consider improving the article to address the issues raised. Removing {{proposed deletion/dated}}
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proposed deletion process, but other
deletion processes exist. In particular, the
speedy deletion process can result in deletion without discussion, and
articles for deletion allows discussion to reach
consensus for deletion.
David Gerard (
talk)
14:00, 3 October 2013 (UTC)
Hello member of Category:Wikipedians who use IRC! You are invited to join an ongoing discussion on Wikipedia talk:IRC/wikipedia-en-help aimed at defining a policy for prerequisites to being a helper in the "#wikipedia-en-help connect" channel in a section titled "New helper policy".
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The article Guievict has been proposed for deletion because of the following concern:
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You may prevent the proposed deletion by removing the {{proposed deletion/dated}}
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Dialectric (
talk)
14:43, 1 May 2015 (UTC)
"Could" is not an adjective, it's a Past form. "Can", and "cant", have no adjective. However, "can" = "is able to", and "can't" = "is unable to", while "is unable" - has an adjective: "unable", so you can say: "it is an error of table unable to be displayed".
Just losing weight overall could help, by eating fewer total calories. Of course, you need to get enough protein (I think 55 g per day is the general recommendation, but can go lower if your doctor requires it), but no excess. Beans, fish (not fried !), and nuts (not salted !) are a good choice for protein sources. Vegetables provide lots of nutrients but few calories, so they are a good choice. Keep the carbs low, such as grains, potatoes, and sugar. Also avoid artificial sweeteners. Surprisingly, eating fats don't seem to make you gain fat, but limit saturated fats and avoid artificial trans fats entirely.
You left open the possibility or anaerobic exercise. If so, any exercise can help, even just walking a bit each day. StuRat ( talk) 14:21, 9 July 2015 (UTC)
From your method of editing and the subject material that interests you I suspect you may be a sock of User Sagittarian Milky Way. See the discussion here. My apology for the delay in notification. μηδείς ( talk) 21:16, 21 September 2015 (UTC)
![]() | This help request has been answered. If you need more help, you can , contact the responding user(s) directly on their user talk page, or consider visiting the Teahouse. |
I have made a long edit on WP:sandbox before (look here). I would like to know if such kind of edit is inappropriate. And did I violate any guidelines of editing sandbox?
Justin545 ( talk) 01:59, 26 September 2015 (UTC)
A tag has been placed on User:Justin545/Blog comments requesting that it be speedily deleted from Wikipedia. This has been done under section U5 of the criteria for speedy deletion, because the page appears to consist of writings, information, discussions, and/or activities not closely related to Wikipedia's goals. Please note that Wikipedia is not a free Web hosting service. Under the criteria for speedy deletion, such pages may be deleted at any time.
If you think this page should not be deleted for this reason, you may contest the nomination by visiting the page and clicking the button labelled "Contest this speedy deletion". This will give you the opportunity to explain why you believe the page should not be deleted. However, be aware that once a page is tagged for speedy deletion, it may be removed without delay. Please do not remove the speedy deletion tag from the page yourself, but do not hesitate to add information in line with Wikipedia's policies and guidelines. If the page is deleted, and you wish to retrieve the deleted material for future reference or improvement, then please contact the deleting administrator, or if you have already done so, you can place a request here. Mys_721tx ( talk) 09:20, 3 November 2015 (UTC)
Hi,
You appear to be eligible to vote in the current
Arbitration Committee election. The
Arbitration Committee is the panel of editors responsible for conducting the Wikipedia
arbitration process. It has the authority to enact binding solutions for disputes between editors, primarily related to serious behavioural issues that the community has been unable to resolve. This includes the ability to impose
site bans,
topic bans, editing restrictions, and other measures needed to maintain our editing environment. The
arbitration policy describes the Committee's roles and responsibilities in greater detail. If you wish to participate, you are welcome to
review the candidates' statements and submit your choices on
the voting page. For the Election committee,
MediaWiki message delivery (
talk)
13:35, 24 November 2015 (UTC)
Hello, Justin545. Voting in the 2017 Arbitration Committee elections is now open until 23.59 on Sunday, 10 December. All users who registered an account before Saturday, 28 October 2017, made at least 150 mainspace edits before Wednesday, 1 November 2017 and are not currently blocked are eligible to vote. Users with alternate accounts may only vote once.
The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail.
If you wish to participate in the 2017 election, please review the candidates and submit your choices on the voting page. MediaWiki message delivery ( talk) 18:42, 3 December 2017 (UTC)
Hello, Justin545. Voting in the 2018 Arbitration Committee elections is now open until 23.59 on Sunday, 3 December. All users who registered an account before Sunday, 28 October 2018, made at least 150 mainspace edits before Thursday, 1 November 2018 and are not currently blocked are eligible to vote. Users with alternate accounts may only vote once.
The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail.
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Hello! Voting in the 2022 Arbitration Committee elections is now open until 23:59 (UTC) on Monday, 12 December 2022. All eligible users are allowed to vote. Users with alternate accounts may only vote once.
The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail.
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MediaWiki message delivery (
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00:42, 29 November 2022 (UTC)
Hello! Voting in the 2023 Arbitration Committee elections is now open until 23:59 (UTC) on Monday, 11 December 2023. All eligible users are allowed to vote. Users with alternate accounts may only vote once.
The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail.
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MediaWiki message delivery (
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00:28, 28 November 2023 (UTC)
(Courtesy ping of
Jonesey95, who is often helpful in fixing lint errors.) Justin545: You recently edited
Template:Numbered block, and now there are several
pages with Multiline table in list lint errors. I started in User space and fixed two pages,
User:Justin545 and
User:Mim.cis/sandbox/Derivation of Landmark LDDMM Conditions, before I discovered that changing {{NumBlk||...}}
to {{NumBlk|:|...}}
made the lint error go away, and only then did I discover that you had edited
Template:Numbered block. So I am pausing now to inform you of this. Please see if you can fix
Template:Numbered block to avoid the Multiline table in list lint error. —
Anomalocaris (
talk)
05:44, 2 May 2024 (UTC)
NumBlk
if I understand correctly. Probably I need to revert it and try to figure out the cause ...
Justin545 (
talk)
06:54, 2 May 2024 (UTC)