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Something's not right. Try clicking through a few of the polyhedra listed as having 16 vertices. Several of them state 15 vertices on the resulting page. I'll look into it a bit closer when I finish the task at hand. -- Andybak ( talk) 19:37, 26 January 2021 (UTC)
I want to know why this page is so incomplete. You police the page against input, but leave it so inept. Who are you and why don't you care? Jmalick99 ( talk) 02:07, 26 January 2023 (UTC)
I want to know why this page is so incomplete. Y9ou police the page against input,but leave it inept.n Who are the police and why don't they care? Jmalick99 ( talk) 02:09, 26 January 2023 (UTC)
Even though it is explained in the text, the title is slightly misleading. Maybe a change to a different title (for example, "List of named polyhedrons with few vertices") would be better.
Also, "topologically equivalent" sounds strange to me: all polyhedron are homeomorphic to the sphere $S^2$. Did you mean "combinatorially equivalent"? — Preceding unsigned comment added by 210.119.101.12 ( talk) 12:25, 14 September 2023 (UTC)
| This article is rated List-class on Wikipedia's
content assessment scale. It is of interest to the following WikiProjects: | ||||||||||||||||||||
| |||||||||||||||||||||
Something's not right. Try clicking through a few of the polyhedra listed as having 16 vertices. Several of them state 15 vertices on the resulting page. I'll look into it a bit closer when I finish the task at hand. -- Andybak ( talk) 19:37, 26 January 2021 (UTC)
I want to know why this page is so incomplete. You police the page against input, but leave it so inept. Who are you and why don't you care? Jmalick99 ( talk) 02:07, 26 January 2023 (UTC)
I want to know why this page is so incomplete. Y9ou police the page against input,but leave it inept.n Who are the police and why don't they care? Jmalick99 ( talk) 02:09, 26 January 2023 (UTC)
Even though it is explained in the text, the title is slightly misleading. Maybe a change to a different title (for example, "List of named polyhedrons with few vertices") would be better.
Also, "topologically equivalent" sounds strange to me: all polyhedron are homeomorphic to the sphere $S^2$. Did you mean "combinatorially equivalent"? — Preceding unsigned comment added by 210.119.101.12 ( talk) 12:25, 14 September 2023 (UTC)