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The diagram at top right of the page has an error in that tiles 6.11 and 7.9 are the same. (Counting down and across.)
One should be replaced by the tile that looks like this:
X XX XX X X
In other words tile 7.9 could be altered by sliding the single square to the right up one place.
Frankd48 ( talk) 05:26, 18 April 2009 (UTC)
This question regards multiple polymino articles. Does the statement "All but four heptominoes are capable of tiling the plane" mean that they tile it individually or in combination with other heptominoes? Moberg ( talk) 13:44, 16 July 2011 (UTC)
The article says:
Although a complete set of 108 heptominoes has a total of 756 squares, it is not possible to pack them into a rectangle. The proof of this is trivial, since there is one heptomino which has a hole. [1] It is also impossible to pack them into a 757-square rectangle with a one-square hole because 757 is a prime number.
All but four heptominoes are capable of tiling the plane; the one with a hole is one such example. [2]
Using a new term, regular polyomino meaning a polyomino without a hole, can we pack all regular heptominos into a rectangle?? Georgia guy ( talk) 19:47, 2 February 2012 (UTC)
References
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cite book}}
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{{
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![]() | This article is rated Start-class on Wikipedia's
content assessment scale. It is of interest to the following WikiProjects: | ||||||||||
|
The diagram at top right of the page has an error in that tiles 6.11 and 7.9 are the same. (Counting down and across.)
One should be replaced by the tile that looks like this:
X XX XX X X
In other words tile 7.9 could be altered by sliding the single square to the right up one place.
Frankd48 ( talk) 05:26, 18 April 2009 (UTC)
This question regards multiple polymino articles. Does the statement "All but four heptominoes are capable of tiling the plane" mean that they tile it individually or in combination with other heptominoes? Moberg ( talk) 13:44, 16 July 2011 (UTC)
The article says:
Although a complete set of 108 heptominoes has a total of 756 squares, it is not possible to pack them into a rectangle. The proof of this is trivial, since there is one heptomino which has a hole. [1] It is also impossible to pack them into a 757-square rectangle with a one-square hole because 757 is a prime number.
All but four heptominoes are capable of tiling the plane; the one with a hole is one such example. [2]
Using a new term, regular polyomino meaning a polyomino without a hole, can we pack all regular heptominos into a rectangle?? Georgia guy ( talk) 19:47, 2 February 2012 (UTC)
References
{{
cite book}}
: Unknown parameter |coauthors=
ignored (|author=
suggested) (
help)
{{
cite journal}}
: Unknown parameter |month=
ignored (
help)