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Is there any reason why the ordered phase always has to be lower in temperature compared to the disordered phase? Are there any counterexamples? AnonyScientist ( talk) 08:29, 4 July 2008 (UTC)
This article goes straight to the math, without giving any concrete example of what quantity would be governed by such laws. In other words, it's mostly useless to anyone who doesn't already know the meaning of the topic. Homunq ( talk) 09:22, 23 October 2011 (UTC)
I offer a very simple explanation: The heat capacity of the Ising model is not the isochoric heat capacity, for the Ising model does not have a volume as a parameter. The C of the Ising model is a heat capacity under the constraint that the “exchange reaction” spin-up ↔ spin-down is in a kind of chemical equilibrium. The equivalent of a real fluid would be an Ising model where the spin-up/spin-down ratio is fixed. Thermo53 ( talk) 20:30, 7 April 2022 (UTC)
![]() | This article is rated Start-class on Wikipedia's
content assessment scale. It is of interest to the following WikiProjects: | ||||||||||
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Is there any reason why the ordered phase always has to be lower in temperature compared to the disordered phase? Are there any counterexamples? AnonyScientist ( talk) 08:29, 4 July 2008 (UTC)
This article goes straight to the math, without giving any concrete example of what quantity would be governed by such laws. In other words, it's mostly useless to anyone who doesn't already know the meaning of the topic. Homunq ( talk) 09:22, 23 October 2011 (UTC)
I offer a very simple explanation: The heat capacity of the Ising model is not the isochoric heat capacity, for the Ising model does not have a volume as a parameter. The C of the Ising model is a heat capacity under the constraint that the “exchange reaction” spin-up ↔ spin-down is in a kind of chemical equilibrium. The equivalent of a real fluid would be an Ising model where the spin-up/spin-down ratio is fixed. Thermo53 ( talk) 20:30, 7 April 2022 (UTC)