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By comparison to the previous section re the sum of three cubes of positive integers a, b, c, d, a similar question can be asked: What is the condition for the divisibility of this sum of four cubes by the sum of these numbers?-- 109.166.137.3 ( talk) 10:30, 15 October 2019 (UTC)
This is the searched identity. It appears that a sum of products appears, the number of products beeing determined by n choose k where k=3. How is this identity modified for the case of 5 cubes, 6 cubes.. and so on? (This determins the question below re generalization involving binomial coefficients).-- 109.166.137.3 ( talk) 18:53, 16 October 2019 (UTC)
What's the largest prime that doesn't have an Atkin–Goldwasser–Kilian–Morain certificate? 2 must not have one, since each AGKM certificate uses a smaller prime q; and for 3, 5 and 7, the lower bound on q works out larger than the previous prime. But does 11 have one? Neon Merlin 17:23, 15 October 2019 (UTC)
Mathematics desk | ||
---|---|---|
< October 14 | << Sep | October | Nov >> | October 16 > |
Welcome to the Wikipedia Mathematics Reference Desk Archives |
---|
The page you are currently viewing is a transcluded archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages. |
By comparison to the previous section re the sum of three cubes of positive integers a, b, c, d, a similar question can be asked: What is the condition for the divisibility of this sum of four cubes by the sum of these numbers?-- 109.166.137.3 ( talk) 10:30, 15 October 2019 (UTC)
This is the searched identity. It appears that a sum of products appears, the number of products beeing determined by n choose k where k=3. How is this identity modified for the case of 5 cubes, 6 cubes.. and so on? (This determins the question below re generalization involving binomial coefficients).-- 109.166.137.3 ( talk) 18:53, 16 October 2019 (UTC)
What's the largest prime that doesn't have an Atkin–Goldwasser–Kilian–Morain certificate? 2 must not have one, since each AGKM certificate uses a smaller prime q; and for 3, 5 and 7, the lower bound on q works out larger than the previous prime. But does 11 have one? Neon Merlin 17:23, 15 October 2019 (UTC)