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There's a solution but it seems more complicated than necessary. [1] If you replace the cotangent inverse with tangent, wouldn't the substitution by parts go a lot smoother? u=tan x, so du=sec^2 x dx and the integral of x sec^2 x can be obtained by integration by parts again, dv = sec^2 x dx which when integrated becomes tan x and then I get terms cancelling out and finally
ln |sec x| +C
Where did I go wrong? Imagine Reason ( talk) 20:49, 10 September 2016 (UTC)
Mathematics desk | ||
---|---|---|
< September 9 | << Aug | September | Oct >> | Current desk > |
Welcome to the Wikipedia Mathematics Reference Desk Archives |
---|
The page you are currently viewing is an archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages. |
There's a solution but it seems more complicated than necessary. [1] If you replace the cotangent inverse with tangent, wouldn't the substitution by parts go a lot smoother? u=tan x, so du=sec^2 x dx and the integral of x sec^2 x can be obtained by integration by parts again, dv = sec^2 x dx which when integrated becomes tan x and then I get terms cancelling out and finally
ln |sec x| +C
Where did I go wrong? Imagine Reason ( talk) 20:49, 10 September 2016 (UTC)