Mathematics desk | ||
---|---|---|
< January 13 | << Dec | January | Feb >> | January 15 > |
Welcome to the Wikipedia Mathematics Reference Desk Archives |
---|
The page you are currently viewing is a transcluded archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages. |
ƒ(n)=2^n(n-1)^n(n+2)
ƒ(n)=2n(n-1)n(n+2)
ƒ(n)=2n(n-1)n(n+2)
All primes can be described,
Pβ×[(Pα+Pα)×β]β −Pα = [(Pα+Pα)×β](Pα+Pα)×β −Pα
where Pα = 1, and β = {1,2,3,4,5}. For example,
32×(25)−1 = 210−1
→ 1023 = 1023
Which is correct. But, is this generalization always true? Can Primes always be factored in this way? — Preceding unsigned comment added by 99.182.38.146 ( talk) 05:07, 14 January 2014 (UTC)
Mathematics desk | ||
---|---|---|
< January 13 | << Dec | January | Feb >> | January 15 > |
Welcome to the Wikipedia Mathematics Reference Desk Archives |
---|
The page you are currently viewing is a transcluded archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages. |
ƒ(n)=2^n(n-1)^n(n+2)
ƒ(n)=2n(n-1)n(n+2)
ƒ(n)=2n(n-1)n(n+2)
All primes can be described,
Pβ×[(Pα+Pα)×β]β −Pα = [(Pα+Pα)×β](Pα+Pα)×β −Pα
where Pα = 1, and β = {1,2,3,4,5}. For example,
32×(25)−1 = 210−1
→ 1023 = 1023
Which is correct. But, is this generalization always true? Can Primes always be factored in this way? — Preceding unsigned comment added by 99.182.38.146 ( talk) 05:07, 14 January 2014 (UTC)