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January 1 Information

Product distribution of piecewise defined probability density functions

Can anyone give me a complete treatment / algorithm (the formula in the article is completely inadequate) of the product distribution of any two functions? I am interested in cases where the functions may be piecewise and range across positive and negative values. 68.0.144.214 ( talk) 17:32, 1 January 2014 (UTC) reply

Having looked at the article, I don't understand the formula for the case of identical distributions each with density function f, surely a single-parameter function. So how can f appear with two parameters in the integral? Why is it not just the case above with the product being f(x)f(z/x)? 31.54.113.130 ( talk) 20:36, 2 January 2014 (UTC) reply
It should be f(x)f(z/x); I fixed the formula in the article so it should be correct now. -- RDBury ( talk) 02:18, 3 January 2014 (UTC) reply
From Wikipedia, the free encyclopedia
Mathematics desk
< December 31 << Dec | January | Feb >> Current desk >
Welcome to the Wikipedia Mathematics Reference Desk Archives
The page you are currently viewing is an archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages.


January 1 Information

Product distribution of piecewise defined probability density functions

Can anyone give me a complete treatment / algorithm (the formula in the article is completely inadequate) of the product distribution of any two functions? I am interested in cases where the functions may be piecewise and range across positive and negative values. 68.0.144.214 ( talk) 17:32, 1 January 2014 (UTC) reply

Having looked at the article, I don't understand the formula for the case of identical distributions each with density function f, surely a single-parameter function. So how can f appear with two parameters in the integral? Why is it not just the case above with the product being f(x)f(z/x)? 31.54.113.130 ( talk) 20:36, 2 January 2014 (UTC) reply
It should be f(x)f(z/x); I fixed the formula in the article so it should be correct now. -- RDBury ( talk) 02:18, 3 January 2014 (UTC) reply

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