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The appearance of one word in Gothic alphabet (𐌲𐌿𐍄𐌹𐍃𐌺) on another RD made me wonder: How can I know what font my computer (or browser) chooses for a given obscure segment of Unicode? — Tamfang ( talk) 00:01, 19 August 2012 (UTC)
Firefox, Snow Leopard, (Language). — Tamfang ( talk) 00:48, 20 August 2012 (UTC)
How difficult is it to remove illegal copies of your books/games/software online? Why is it so easy to find something, not only through emule and torrent, which are decentralized, but also for direct download? The copyright owners shouldn't have any problem finding those either. Comploose ( talk) 00:06, 19 August 2012 (UTC)
It's virtually impossible. Making illegal copies of things mostly useless is not so hard though: make them call you up and prove you are the purchaser before the software will run (or the like). The only problems with this approach is that 1) it's really annoying to those who weren't trying to use an illegal copy in the first place, and 2) while people using unpaid for copies of your software aren't generating you revenue at the moment, you are still generating demand for your software, which can often lead to revenue should the persons using it ever want to appear more squeaky clean themselves. ¦ Reisio ( talk) 17:35, 19 August 2012 (UTC)
What is the cheapest, the best, and the most accurate drawing pad for PC. — Preceding unsigned comment added by 76.16.47.115 ( talk) 03:45, 19 August 2012 (UTC)
Sure if that helps you. — Preceding unsigned comment added by 76.16.47.115 ( talk) 13:49, 19 August 2012 (UTC)
So, I lost the charger for my camera, it's one of those ones with its own battery that needs taking out and recharging rather than just buying more from the shop, but I need it for tomorrow, so I need to find a shop that sells a new one very soon. I thought, try PC world, seeing as that's where I got the camera originally, but no, thousands of accessories, no chargers. any other thoughts?
Kitutal ( talk) 12:00, 19 August 2012 (UTC)
I thought the chances of someone coming from this exact area were rather low. but if you're sure, it's a panasonic lumix dmc-fs16 in east kent Kitutal ( talk) 14:00, 19 August 2012 (UTC)
ah, but could any online seller deliver by tomorrow morning? meanwhile the link brings up argos, currys and comet, argos has sold out anywhere near here, and the others have nothing even similar on sale... Kitutal ( talk) 18:06, 19 August 2012 (UTC)
Go to a mobile phone shop and see if they have a universal charger that fits your battery. Bring your battery to the store to try different models. 69.228.170.132 ( talk) 06:07, 20 August 2012 (UTC)
PD2 = []
for D1 in range(10):
PD2 = x for x in range(10) if not x in D1]]
for D2 in PD2:
PD3 = x for x in range(10) if not x in D1, D2]]
for D3 in PD3:
PD4 = x for x in range(10) if not x in D1, D2, D3]]
for D4 in PD4:
PD5 = x for x in range(10) if not x in D1, D2, D3, D4]]
for D5 in PD5:
PD6 = x for x in range(10) if not x in D1, D2, D3, D4, D5]]
for D6 in PD6:
PD7 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6]]
for D7 in PD7:
PD8 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6, D7]]
for D8 in PD8:
PD9 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6, D7, D8]]
for D9 in PD9:
PD0 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6, D7, D8, D9]]
for D0 in PD0:
PandigitalNumber = int(str(D1) + str(D2) + str(D3) + str(D4) + str(D5) + str(D6) + str(D7) + str(D8) + str(D9) + str(D0))
— Preceding unsigned comment added by 220.255.2.58 ( talk) 18:28, 19 August 2012 (UTC)
from itertools import permutations
def generate_pandigital(length):
"""Generates zerofull pandigital numbers."""
for n in permutations("0123456789"[:length]):
yield "".join(n)
→ Σ σ ς. 18:52, 19 August 2012 (UTC)
That is a good exercise in using recursion. Note Σ's solution has some problems, like not eliminating results that begin with 0. Is this a homework exercise? If yes, we should supposedly only give hints and advice, rather than working solutions. 69.228.170.132 ( talk) 05:28, 20 August 2012 (UTC)
I'm starting to think seriously about going in blogging once again, but kinda think social networking is like blogging. I have had a few of them in the past, but have given them up for social networking and etc. I'm still undecided on where should I blog from. My preference is a free vs paid or combo of worlds. — Preceding unsigned comment added by Mybodymyself ( talk • contribs) 21:15, 19 August 2012 (UTC)
Thank you for both of your answers to my question here.-- Jessica A Bruno ( talk) 01:27, 20 August 2012 (UTC)
I'm back to tell you that I have decided to go back into blogging again.-- Jessica A Bruno ( talk) 01:48, 20 August 2012 (UTC)
This was kind of interesting. It says it's better to pay for and host your own blog, instead of using something like blogspot/wordpress. (This can be done at very low cost). 69.228.170.132 ( talk) 06:04, 20 August 2012 (UTC)
Hmm interesting and I'm still a little unsure how I think about this.-- Jessica A Bruno ( talk) 18:09, 20 August 2012 (UTC)
Computing desk | ||
---|---|---|
< August 18 | << Jul | August | Sep >> | August 20 > |
Welcome to the Wikipedia Computing Reference Desk Archives |
---|
The page you are currently viewing is an archive page. While you can leave answers for any questions shown below, please ask new questions on one of the current reference desk pages. |
The appearance of one word in Gothic alphabet (𐌲𐌿𐍄𐌹𐍃𐌺) on another RD made me wonder: How can I know what font my computer (or browser) chooses for a given obscure segment of Unicode? — Tamfang ( talk) 00:01, 19 August 2012 (UTC)
Firefox, Snow Leopard, (Language). — Tamfang ( talk) 00:48, 20 August 2012 (UTC)
How difficult is it to remove illegal copies of your books/games/software online? Why is it so easy to find something, not only through emule and torrent, which are decentralized, but also for direct download? The copyright owners shouldn't have any problem finding those either. Comploose ( talk) 00:06, 19 August 2012 (UTC)
It's virtually impossible. Making illegal copies of things mostly useless is not so hard though: make them call you up and prove you are the purchaser before the software will run (or the like). The only problems with this approach is that 1) it's really annoying to those who weren't trying to use an illegal copy in the first place, and 2) while people using unpaid for copies of your software aren't generating you revenue at the moment, you are still generating demand for your software, which can often lead to revenue should the persons using it ever want to appear more squeaky clean themselves. ¦ Reisio ( talk) 17:35, 19 August 2012 (UTC)
What is the cheapest, the best, and the most accurate drawing pad for PC. — Preceding unsigned comment added by 76.16.47.115 ( talk) 03:45, 19 August 2012 (UTC)
Sure if that helps you. — Preceding unsigned comment added by 76.16.47.115 ( talk) 13:49, 19 August 2012 (UTC)
So, I lost the charger for my camera, it's one of those ones with its own battery that needs taking out and recharging rather than just buying more from the shop, but I need it for tomorrow, so I need to find a shop that sells a new one very soon. I thought, try PC world, seeing as that's where I got the camera originally, but no, thousands of accessories, no chargers. any other thoughts?
Kitutal ( talk) 12:00, 19 August 2012 (UTC)
I thought the chances of someone coming from this exact area were rather low. but if you're sure, it's a panasonic lumix dmc-fs16 in east kent Kitutal ( talk) 14:00, 19 August 2012 (UTC)
ah, but could any online seller deliver by tomorrow morning? meanwhile the link brings up argos, currys and comet, argos has sold out anywhere near here, and the others have nothing even similar on sale... Kitutal ( talk) 18:06, 19 August 2012 (UTC)
Go to a mobile phone shop and see if they have a universal charger that fits your battery. Bring your battery to the store to try different models. 69.228.170.132 ( talk) 06:07, 20 August 2012 (UTC)
PD2 = []
for D1 in range(10):
PD2 = x for x in range(10) if not x in D1]]
for D2 in PD2:
PD3 = x for x in range(10) if not x in D1, D2]]
for D3 in PD3:
PD4 = x for x in range(10) if not x in D1, D2, D3]]
for D4 in PD4:
PD5 = x for x in range(10) if not x in D1, D2, D3, D4]]
for D5 in PD5:
PD6 = x for x in range(10) if not x in D1, D2, D3, D4, D5]]
for D6 in PD6:
PD7 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6]]
for D7 in PD7:
PD8 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6, D7]]
for D8 in PD8:
PD9 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6, D7, D8]]
for D9 in PD9:
PD0 = x for x in range(10) if not x in D1, D2, D3, D4, D5, D6, D7, D8, D9]]
for D0 in PD0:
PandigitalNumber = int(str(D1) + str(D2) + str(D3) + str(D4) + str(D5) + str(D6) + str(D7) + str(D8) + str(D9) + str(D0))
— Preceding unsigned comment added by 220.255.2.58 ( talk) 18:28, 19 August 2012 (UTC)
from itertools import permutations
def generate_pandigital(length):
"""Generates zerofull pandigital numbers."""
for n in permutations("0123456789"[:length]):
yield "".join(n)
→ Σ σ ς. 18:52, 19 August 2012 (UTC)
That is a good exercise in using recursion. Note Σ's solution has some problems, like not eliminating results that begin with 0. Is this a homework exercise? If yes, we should supposedly only give hints and advice, rather than working solutions. 69.228.170.132 ( talk) 05:28, 20 August 2012 (UTC)
I'm starting to think seriously about going in blogging once again, but kinda think social networking is like blogging. I have had a few of them in the past, but have given them up for social networking and etc. I'm still undecided on where should I blog from. My preference is a free vs paid or combo of worlds. — Preceding unsigned comment added by Mybodymyself ( talk • contribs) 21:15, 19 August 2012 (UTC)
Thank you for both of your answers to my question here.-- Jessica A Bruno ( talk) 01:27, 20 August 2012 (UTC)
I'm back to tell you that I have decided to go back into blogging again.-- Jessica A Bruno ( talk) 01:48, 20 August 2012 (UTC)
This was kind of interesting. It says it's better to pay for and host your own blog, instead of using something like blogspot/wordpress. (This can be done at very low cost). 69.228.170.132 ( talk) 06:04, 20 August 2012 (UTC)
Hmm interesting and I'm still a little unsure how I think about this.-- Jessica A Bruno ( talk) 18:09, 20 August 2012 (UTC)