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"Because these valves do not start opening until the system reaches 90% of full pressure, the efficiency of the system is protected.." ^[1]

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Going from 56.234133 µV to dBµV:

${\displaystyle G_{\mathrm {dB} }=20\log _{10}{\bigg (}{\frac {56.234133~\mu \,\!V\times 10^{6}}{1~V}}{\bigg )}=35~\mathrm {dB} \,}$

Going from 35 dBµV to voltage:

${\displaystyle G=10^{-6}\times 10^{\frac {35~\mathrm {dB} }{20}}=56.234133...~\mu \,\!V\approx 56~\mu \,\!V\,}$

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Note 1: The multiplier of the Phenom applies to the 200 MHz HyperTransport base clock.

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! Quantity !! Unit<br />[[[Watt]]]
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| Power || 1000
|}

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Curie's Law can be derived by considering a substance with noninteracting magnetic moments with angular momentum J. If orbital contributions to the magnetic moment are negligible (a common case), then in what follows J = S. If we apply a magnetic field along what we choose to call the z-axis, the energy levels of each paramagnetic center will experience Zeeman splitting of its energy levels, each with a z-component labeled by MJ (or just MS for the spin-only magnetic case). Applying semiclassical Boltzmann statistics, the molar magnetization of such a substance is ${\displaystyle N_{A}{\bar {m}}={\frac {N_{A}\sum \limits _{M_{J}=-J}^{J}{\mu _{M_{J}}e^{{-E_{M_{J}}}/{k_{B}T}\;}}}{\sum \limits _{M_{J}=-J}^{J}{e^{{-E_{M_{J}}}/{k_{B}T}\;}}}}={\frac {N_{A}\sum \limits _{M_{J}=-J}^{J}{M_{J}g_{J}\mu _{B}e^{{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;}}}{\sum \limits _{M_{J}=-J}^{J}{e^{{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;}}}}}$. Where ${\displaystyle \mu _{M_{J}}}$ is the z-component of the magnetic moment for each Zeeman level, so ${\displaystyle \mu _{M_{J}}=M_{J}g_{J}\mu _{B}}$ – μB is called the Bohr Magneton and gJ is the Landé g-factor, which reduces to the free-electron g-factor, gS when J = S. (in this treatment, we assume that the x- and y-components of the magnetization, averaged over all molecules, cancel out because the field applied along the z-axis leave them randomly oriented.) The energy of each Zeeman level is ${\displaystyle E_{M_{J}}=-M_{J}g_{J}\mu _{B}H}$. For temperatures over a few K, ${\displaystyle {M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;\ll 1}$, and we can apply the approximation ${\displaystyle e^{{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;}\simeq 1+{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;}$ : ${\displaystyle {\bar {m}}={\frac {\sum \limits _{M_{J}=-J}^{J}{M_{J}g_{J}\mu _{B}e^{{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;}}}{\sum \limits _{M_{J}=-J}^{J}{e^{{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;}}}}\simeq g_{J}\mu _{B}{\frac {\sum \limits _{M_{J}=-J}^{J}{M_{J}\left(1+{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;\right)}}{\sum \limits _{M_{J}=-J}^{J}{\left(1+{M_{J}g_{J}\mu _{B}H}/{k_{B}T}\;\right)}}}={\frac {g_{J}^{2}\mu _{B}^{2}H}{k_{B}T}}{\frac {\sum \limits _{-J}^{J}{M_{J}^{2}}}{\sum \limits _{M_{J}=-J}^{J}{\left(1\right)}}}}$, which yields... ${\displaystyle {\bar {m}}={\frac {g_{J}^{2}\mu _{B}^{2}H}{3k_{B}T}}J(J+1)}$. The molar bulk magnetization is then ${\displaystyle M=N_{\text{A}}{\bar {m}}={\frac {N_{\text{A }}}{3k_{B}T}}\left[g_{J}^{2}J(J+1)\mu _{B}^{2}\right]H}$, and the molar susceptibility is given by ${\displaystyle \chi _{m}={\frac {\partial M}{\partial H}}={\frac {N_{\text{A }}}{3k_{B}T}}\mu _{\mathrm {eff} }^{2}{\text{ ; and }}\mu _{\mathrm {eff} }=g_{J}{\sqrt {J(J+1)}}\mu _{B}}$.

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