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Query the point being made in the final para. Is it about Q-linear functions, eg take a Hamel basis for R over Q, define a function by Q-linearity on the b in it, such as b/|b|, tweak to make bounded?

Charles Matthews 09:13, 19 Feb 2004 (UTC)

I don't know anything specifically about linear functions on R over Q, but I know there exist linear functions on R over R that are not f(x) = ax. My topology book mentions one discovered by F. B. Jones. Its graph is connected but not compact. CyborgTosser

I think you need to clarify that. All the conventional-sense linear functions of that kind are multiplication by constants. The ax+b functions are presumably not what you mean.

Charles Matthews 22:34, 21 Feb 2004 (UTC)

My mistake. The function I mention only satisfies superposition, which would make it linear over Q, not R. CyborgTosser

Page now amended. Charles Matthews 09:03, 11 Mar 2004 (UTC) (Funny, I could have sworn I did, yesterday, but the page history says not ... must be an edit that didn't make it to the far end ... CT has done the necessary now. Charles Matthews)

From Wikipedia, the free encyclopedia

Query the point being made in the final para. Is it about Q-linear functions, eg take a Hamel basis for R over Q, define a function by Q-linearity on the b in it, such as b/|b|, tweak to make bounded?

Charles Matthews 09:13, 19 Feb 2004 (UTC)

I don't know anything specifically about linear functions on R over Q, but I know there exist linear functions on R over R that are not f(x) = ax. My topology book mentions one discovered by F. B. Jones. Its graph is connected but not compact. CyborgTosser

I think you need to clarify that. All the conventional-sense linear functions of that kind are multiplication by constants. The ax+b functions are presumably not what you mean.

Charles Matthews 22:34, 21 Feb 2004 (UTC)

My mistake. The function I mention only satisfies superposition, which would make it linear over Q, not R. CyborgTosser

Page now amended. Charles Matthews 09:03, 11 Mar 2004 (UTC) (Funny, I could have sworn I did, yesterday, but the page history says not ... must be an edit that didn't make it to the far end ... CT has done the necessary now. Charles Matthews)


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