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If Rotation does not depend explicitely on time, and the rotation operator is

${\displaystyle R=1+J_{z}d\theta }$ ,

then, ${\displaystyle J_{z}}$ does not depend explicitely on time. Why is it necessary to go through all the commutator computations? — Thurth ( talk) 06:44, 24 March 2009 (UTC) reply

Is rotational invariance related to conformal invariance? Article doesn't say.