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DFH ( talk) 16:01, 6 January 2009 (UTC)
Strictly speaking, shouldn't the expression for Qbd be compensated for the capacitative charge?
i.e. Subtract Q = C.V where C is the gate capacitance and V is the voltage just before breakdown?
DFH (
talk)
16:35, 6 January 2009 (UTC)
![]() | This article is rated Start-class on Wikipedia's
content assessment scale. It is of interest to the following WikiProjects: | ||||||||||
|
DFH ( talk) 16:01, 6 January 2009 (UTC)
Strictly speaking, shouldn't the expression for Qbd be compensated for the capacitative charge?
i.e. Subtract Q = C.V where C is the gate capacitance and V is the voltage just before breakdown?
DFH (
talk)
16:35, 6 January 2009 (UTC)