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According to other wiki pages, Carbon-14 is formed by thermal neutron (0.025 eV) absorption by the nucleus of Nitrogen-14 and the emission of a proton. Is this also considered a beta decay proton emission, or is there some other process involved? What is the energy of the emitted proton? Kenny56 08:04, 7 January 2006 (UTC)
Reading about Carbon-14 formation there is one question: as you said C14 is formed by thermal absorption by the N14 nucleus. 1 p+ is emitted. Okay, but that leaves 1 electron (e-). My question: is the emission of a proton always accompanied by Beta-radiation? So another question: what about the assertion that there is no proton radiation under natural circumstances? Baalu 22:26, 15 June 2006 (UTC)
For a proton to escape a nucleus, the proton separation energy must be negative - the proton is therefore unbound, and tunnels through the Coulomb barrier in a finite time.
Doesn't the proton have to tunnel thru the nuclear strong force barrier, not approach another nucleus's Coulomb barrier? -- Vuo 01:46, 1 November 2006 (UTC)
The proton is already unbound in terms of the nuclear force, and is being held in place by the Coulomb barrier of the nucleus (and a centrifugal barrier if the proton is carrying orbital angular momentum). I know this isn't immediately intuitive, as we think of the Coulomb barrier in the first instance as something that repels external positive charges from the nucleus rather than being able to hold positive charges inside the nucleus. The following diagram illustrates the point: http://personal.ph.surrey.ac.uk/~phs1wc/CD-sirius/science/scigif6.gif (a nucleon is unbound if it is above the zero potential line in this diagram - the shape of the potential is a sum of the nuclear force, producing the below-zero well containing nuclear bound states, and the Coulomb and centrifugal forces which produce the long above-zero tail) ---158.180.64.10, January 2007
Should that be iron-54? Man with two legs 20:25, 30 March 2007 (UTC)
No, it really is Iron 45. A very exotic (and short-lived) nucleus!
Lutetium-151 and Thulium-147 are so far from the stable masses of 175 and 169 respectively, that I question whether those are real. Dragons flight ( talk) 19:42, 23 December 2007 (UTC)
Is proton emission a form of cluster decay, the emitted proton being a hydrogen-nucleus?
In the table in the Radioactive decay article, the definition of cluster decay seems to include proton emission ("nucleus emits a specific type of smaller nucleus..."), but the Cluster decay article defines cluster decay in terms of clusters of protons and neutrons! Eroica ( talk) 08:07, 9 January 2008 (UTC)
![]() | This article is rated Start-class on Wikipedia's
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According to other wiki pages, Carbon-14 is formed by thermal neutron (0.025 eV) absorption by the nucleus of Nitrogen-14 and the emission of a proton. Is this also considered a beta decay proton emission, or is there some other process involved? What is the energy of the emitted proton? Kenny56 08:04, 7 January 2006 (UTC)
Reading about Carbon-14 formation there is one question: as you said C14 is formed by thermal absorption by the N14 nucleus. 1 p+ is emitted. Okay, but that leaves 1 electron (e-). My question: is the emission of a proton always accompanied by Beta-radiation? So another question: what about the assertion that there is no proton radiation under natural circumstances? Baalu 22:26, 15 June 2006 (UTC)
For a proton to escape a nucleus, the proton separation energy must be negative - the proton is therefore unbound, and tunnels through the Coulomb barrier in a finite time.
Doesn't the proton have to tunnel thru the nuclear strong force barrier, not approach another nucleus's Coulomb barrier? -- Vuo 01:46, 1 November 2006 (UTC)
The proton is already unbound in terms of the nuclear force, and is being held in place by the Coulomb barrier of the nucleus (and a centrifugal barrier if the proton is carrying orbital angular momentum). I know this isn't immediately intuitive, as we think of the Coulomb barrier in the first instance as something that repels external positive charges from the nucleus rather than being able to hold positive charges inside the nucleus. The following diagram illustrates the point: http://personal.ph.surrey.ac.uk/~phs1wc/CD-sirius/science/scigif6.gif (a nucleon is unbound if it is above the zero potential line in this diagram - the shape of the potential is a sum of the nuclear force, producing the below-zero well containing nuclear bound states, and the Coulomb and centrifugal forces which produce the long above-zero tail) ---158.180.64.10, January 2007
Should that be iron-54? Man with two legs 20:25, 30 March 2007 (UTC)
No, it really is Iron 45. A very exotic (and short-lived) nucleus!
Lutetium-151 and Thulium-147 are so far from the stable masses of 175 and 169 respectively, that I question whether those are real. Dragons flight ( talk) 19:42, 23 December 2007 (UTC)
Is proton emission a form of cluster decay, the emitted proton being a hydrogen-nucleus?
In the table in the Radioactive decay article, the definition of cluster decay seems to include proton emission ("nucleus emits a specific type of smaller nucleus..."), but the Cluster decay article defines cluster decay in terms of clusters of protons and neutrons! Eroica ( talk) 08:07, 9 January 2008 (UTC)