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as it is now, the two entries "elecitric potential" and "potential" (the very last) are identical. would it not make much more sense to interpret the second potential as gravitational potential? then its SI dimension would be [L² T^-2] (the same as energy/mass), and the multiplication factor would just be c^-2. -- Diogenes2000 ( talk) 02:51, 30 December 2012 (UTC) reply

Here you have all needed conversion factors that covers all SI base units, and if not possible, their unique elements:

into m

• G/c^2 [m/kg]
• c [m/s]
• ((G/(4*pi*(electric constant)))^0.5)/c^2 [m/C]
• (G*k)/c^4 [m/K]

into kg

• c^2/G [kg/m]
• c^3/G [kg/s]
• 1/(G*4*pi*(electric constant))^0.5 [kg/C]
• k/c^2 [kg/K]

into s

• 1/c [s/m]
• G/c^3 [s/kg]
• ((G/(4*pi*(electric constant)))^0.5)/c^3 [s/C]
• (G*k)/c^5 [s/K]

into C

• c^2/((G/(4*pi*(electric constant)))^0.5) [C/m]
• (G*4*pi*(electric constant))^0.5 [C/kg]
• c^3/((G/(4*pi*(electric constant)))^0.5) [C/s]
• (k*(G*4*pi*(electric constant))^0.5)/c^2 [C/K]

into K

• c^4/(G*k) [K/m]
• c^2/k [K/kg]
• c^5/(G*k) [K/s]
• c^2/(k*(G*4*pi*(electric constant))^0.5) [K/C]

All these units represents nothing else than distance along dimension, that makes SI redundant in comparison to geometrized units. I added all these abovementioned factors after proper formatting to article. They can be verified in Google calculator.

This all is exactly equivalent to dividing of one Planck unit by another Planck unit, while using their direct SI values. 83.30.150.203 ( talk) 08:20, 20 January 2024 (UTC) reply

I removed an entire section with a table of conversions. @ Anubub reverted the change, but I took it out again based on WP:BURDEN.

The table entries need a reference. If the entries are trivial, then we don't need the table. If the entries are WP:NOTABLE then they need a reference.

In addition, the practical issue is that entries in the table keep being changed and we have no justification for reverting such changes because we have no reference. Johnjbarton ( talk) 16:09, 24 June 2024 (UTC) reply