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Might I suggest whoever made the nice plot of the pdfs to add a curve for a value of k less than one to the plot, so we can see it diverge at 0? Otherwise people may think the value at the mode is always finite. Btyner 19:29, 11 May 2006 (UTC) reply

like${\displaystyle 1-k/2\,}$ does that mean ${\displaystyle 1-{\frac {k}{2}}or{\frac {1-k}{2}}orneither?}$ —The preceding unsigned comment was added by Tikai ( talk • contribs) 15:14, 11 May 2007 (UTC). reply

Order of operations states that ${\displaystyle 1-k/2}$ is equivalent to ${\displaystyle 1-{\frac {k}{2}}}$. Svyatoslav ( talk) 21:29, 10 December 2012 (UTC) reply

And the variance looks wrong too. I believe the variance approaches ${\displaystyle 1/2}$ as ${\displaystyle k}$ goes to infinity Shabbychef ( talk) 22:16, 13 March 2014 (UTC) Oh, wait, my bad, the ${\displaystyle \mu }$ refers to the mean of the chi, not the means of the normals. This looks fine. Shabbychef ( talk) 22:18, 13 March 2014 (UTC) reply

Does not chi-distribution have only 1 parameter? So the whole use of <math>\chi(x)<\math> is confusing Кирилл С1 ( talk) 20:37, 5 December 2019 (UTC) reply