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Untitled
This definition suggests that a stochastic process can never have more than 1 absorbing set. I have reducible process where certain initial conditions may end up in one of two different sets, and once they enter, they never leave. According to this definition, the union of these two sets is an absorbing set, but what do I call the individual pieces? (I cannot call them irreducible subsets, as both still contain transient components.) — Preceding
unsigned comment added by
71.139.152.215 (
talk) 18:32, 4 August 2012 (UTC)reply
This article is within the scope of WikiProject Mathematics, a collaborative effort to improve the coverage of
mathematics on Wikipedia. If you would like to participate, please visit the project page, where you can join
the discussion and see a list of open tasks.MathematicsWikipedia:WikiProject MathematicsTemplate:WikiProject Mathematicsmathematics articles
This article is within the scope of WikiProject Systems, which collaborates on articles related to
systems and
systems science.SystemsWikipedia:WikiProject SystemsTemplate:WikiProject SystemsSystems articles
This article is within the scope of WikiProject Statistics, a collaborative effort to improve the coverage of
statistics on Wikipedia. If you would like to participate, please visit the project page, where you can join
the discussion and see a list of open tasks.StatisticsWikipedia:WikiProject StatisticsTemplate:WikiProject StatisticsStatistics articles
This article has been rated as Low-importance on the
importance scale.
Untitled
This definition suggests that a stochastic process can never have more than 1 absorbing set. I have reducible process where certain initial conditions may end up in one of two different sets, and once they enter, they never leave. According to this definition, the union of these two sets is an absorbing set, but what do I call the individual pieces? (I cannot call them irreducible subsets, as both still contain transient components.) — Preceding
unsigned comment added by
71.139.152.215 (
talk) 18:32, 4 August 2012 (UTC)reply