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Just a quick note, the overall tournament stats are NOT just an average of the averages of the previous rounds. eg. Phil Taylor's average is NOT 105.15 just because of his previous rounds. Obviously, he threw a lot more darts against Jenkins than he did against Nixon, so his overall average will be closer to 102 than to 107. The overall tournament averages are updated here: http://www.teessidesoftware.no-ip.com/DartsDatabase/EventStats.aspx?EventKey=1280. Andy4226uk ( talk) 00:12, 17 November 2008 (UTC)
Phil Taylor had averages of 91.64, 104.82 and 97.24 in the group stages. add those three up to equal 293.70, giving an average of 97.90.
In the knockouts, he had 103.17, 99.28, 96.86 and 101.75 add those four up to equal 401.06, giving an average of 100.27 (rounded up).
so in total over his seven matches, he had 694.76. if you average that out, that'll give you 99.25 per match. which is reflected here: http://www.teessidesoftware.no-ip.com/DartsDatabase/EventStats.aspx?EventKey=424 Cs-wolves ( talk) 00:45, 17 November 2008 (UTC)
OK, I have thought of an idea to try and make the statistics more accurate. I think it is best to demonstrate it with an example, so I will use Phil Taylor's tournament so far:
Proposed Formula: (Average Game 1*Legs Game 1)+(Avg Game 2*Legs Game 2)... /(total number of legs).
Therefore we have (107.36*5)+(102.94*9)+(104.51*6)+(97.37*18)/38 = 101.13
What do you think? Is this mathematically sound? Andy4226uk ( talk) 12:14, 21 November 2008 (UTC)
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Just a quick note, the overall tournament stats are NOT just an average of the averages of the previous rounds. eg. Phil Taylor's average is NOT 105.15 just because of his previous rounds. Obviously, he threw a lot more darts against Jenkins than he did against Nixon, so his overall average will be closer to 102 than to 107. The overall tournament averages are updated here: http://www.teessidesoftware.no-ip.com/DartsDatabase/EventStats.aspx?EventKey=1280. Andy4226uk ( talk) 00:12, 17 November 2008 (UTC)
Phil Taylor had averages of 91.64, 104.82 and 97.24 in the group stages. add those three up to equal 293.70, giving an average of 97.90.
In the knockouts, he had 103.17, 99.28, 96.86 and 101.75 add those four up to equal 401.06, giving an average of 100.27 (rounded up).
so in total over his seven matches, he had 694.76. if you average that out, that'll give you 99.25 per match. which is reflected here: http://www.teessidesoftware.no-ip.com/DartsDatabase/EventStats.aspx?EventKey=424 Cs-wolves ( talk) 00:45, 17 November 2008 (UTC)
OK, I have thought of an idea to try and make the statistics more accurate. I think it is best to demonstrate it with an example, so I will use Phil Taylor's tournament so far:
Proposed Formula: (Average Game 1*Legs Game 1)+(Avg Game 2*Legs Game 2)... /(total number of legs).
Therefore we have (107.36*5)+(102.94*9)+(104.51*6)+(97.37*18)/38 = 101.13
What do you think? Is this mathematically sound? Andy4226uk ( talk) 12:14, 21 November 2008 (UTC)