From Wikipedia, the free encyclopedia
(Redirected from Locally measurable)

In mathematics, a measure is said to be saturated if every locally measurable set is also measurable. [1] A set , not necessarily measurable, is said to be a locally measurable set if for every measurable set of finite measure, is measurable. -finite measures and measures arising as the restriction of outer measures are saturated.

References

  1. ^ Bogachev, Vladmir (2007). Measure Theory Volume 2. Springer. ISBN  978-3-540-34513-8.
From Wikipedia, the free encyclopedia
(Redirected from Locally measurable)

In mathematics, a measure is said to be saturated if every locally measurable set is also measurable. [1] A set , not necessarily measurable, is said to be a locally measurable set if for every measurable set of finite measure, is measurable. -finite measures and measures arising as the restriction of outer measures are saturated.

References

  1. ^ Bogachev, Vladmir (2007). Measure Theory Volume 2. Springer. ISBN  978-3-540-34513-8.

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