From Wikipedia, the free encyclopedia

In mathematics, the Barbanā€“Davenportā€“Halberstam theorem is a statement about the distribution of prime numbers in an arithmetic progression. It is known that in the long run primes are distributed equally across possible progressions with the same difference. Theorems of the Barbanā€“Davenportā€“Halberstam type give estimates for the error term, determining how close to uniform the distributions are.

Statement

Let a be coprime to q and

be a weighted count of primes in the arithmetic progression a mod q. We have

where φ is Euler's totient function and the error term E is small compared to x. We take a sum of squares of error terms

Then we have

for and every positive A, where O is Landau's Big O notation.

This form of the theorem is due to Gallagher. The result of Barban is valid only for for some B depending on A, and the result of Davenportā€“Halberstam has B = A + 5.

See also

References

  • Hooley, C. (2002). "On theorems of Barban-Davenport-Halberstam type". In Bennett, M. A.; Berndt, B. C.; Boston, N.; Diamond, H. G.; Hildebrand, A. J.; Philipp, W. (eds.). Surveys in number theory: Papers from the millennial conference on number theory. Natick, MA: A K Peters. pp. 75ā€“108. ISBN  1-56881-162-4. Zbl  1039.11057.
From Wikipedia, the free encyclopedia

In mathematics, the Barbanā€“Davenportā€“Halberstam theorem is a statement about the distribution of prime numbers in an arithmetic progression. It is known that in the long run primes are distributed equally across possible progressions with the same difference. Theorems of the Barbanā€“Davenportā€“Halberstam type give estimates for the error term, determining how close to uniform the distributions are.

Statement

Let a be coprime to q and

be a weighted count of primes in the arithmetic progression a mod q. We have

where φ is Euler's totient function and the error term E is small compared to x. We take a sum of squares of error terms

Then we have

for and every positive A, where O is Landau's Big O notation.

This form of the theorem is due to Gallagher. The result of Barban is valid only for for some B depending on A, and the result of Davenportā€“Halberstam has B = A + 5.

See also

References

  • Hooley, C. (2002). "On theorems of Barban-Davenport-Halberstam type". In Bennett, M. A.; Berndt, B. C.; Boston, N.; Diamond, H. G.; Hildebrand, A. J.; Philipp, W. (eds.). Surveys in number theory: Papers from the millennial conference on number theory. Natick, MA: A K Peters. pp. 75ā€“108. ISBN  1-56881-162-4. Zbl  1039.11057.

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